# Beecrowd Problem 1000-1020 Solve by C

**Beecrowd Problem 1000**

Your first program in any programming language is usually "Hello World!". In this first problem all you have to do is print this message on the screen.InputThis problem has no input.OutputYou must print the messageHello World!and then the endline as shown below.

Input Sample |
Output Sample |

Hello World! |

#include <stdio.h> int main() { printf("Hello World!\n"); return 0; }

**Beecrowd Problem 1001**

Read2 variables, namedAandBand make the sum of these two variables, assigning its result to the variableX. PrintXas shown below. Print end line after the result otherwise you will get “Presentation Error”.InputThe input file will contain 2 integer numbers.OutputPrint the letterX(uppercase) with a blank space before and after the equal signal followed by the value of X, according to the following example. Obs.: don't forget the end line after all.

Samples Input |
Samples Output |

10 and 9 | X = 19 |

-10 and 4 | X = -6 |

15 and -7 | X = 8 |

#include <stdio.h>int main() {int A, B, X;scanf("%d %d", &A,&B);X = A + B;printf("X = %d\n", X);return 0;}

**Beecrowd Problem 1002**

The formula to calculate the area of a circumference is defined asA = π . R. Considering to this problem that^{2}π=3.14159: Calculate the area using the formula given in the problem description.InputThe input contains a value of floating point (double precision), that is the variableR.OutputPresent the message "A=" followed by the value of the variable, as in the example bellow, with four places after the decimal point. Use all double precision variables. Like all the problems, don't forget to print the end of line after the result, otherwise you will receive "Presentation Error".

Input Samples |
Output Samples |

2.00 | A=12.5664 |

100.64 | A=31819.3103 |

150.00 | A=70685.7750 |

#include <stdio.h>int main() {double pi = 3.14159;double R, area;scanf("%lf", &R);area = pi * R * R;printf("A=%.4lf\n", area);return 0;}

**Beecrowd Problem 1003**

Read two integer values, in this case, the variablesAandB. After this, calculate the sum between them and assign it to the variableSOMA. Write the value of this variable.InputThe input file contains 2 integer numbers.OutputPrint the message "SOMA" with all the capital letters, with a blank space before and after the equal signal followed by the corresponding value to the sum of A and B. Like all the problems, don't forget to print the end of line, otherwise you will receive "Presentation Error"

Input Samples |
Output Samples |

30 and 10 | SOMA = 40 |

-30 and 10 | SOMA = -20 |

0 and 0 | SOMA = 0 |

#include <stdio.h>int main() {int A, B, SOMA;scanf("%d %d", &A, &B);SOMA = A + B;printf("SOMA = %d\n", SOMA);return 0;}

**Beecrowd Problem 1003**

Read two integer values. After this, calculate the product between them and store the result in a variable namedPROD. Print the result like the example below. Do not forget to print the end of line after the result, otherwise you will receive“Presentation Error”.InputThe input file contains 2 integer numbers.OutputPrint the message "PROD" andPRODaccording to the following example, with a blank space before and after the equal signal.

Input Samples |
Output Samples |

3 and 9 | PROD = 27 |

-30 and 10 | PROD = -300 |

0 and 9 | PROD = 0 |

#include <stdio.h>int main() {int a, b, prod;scanf("%d %d", &a, &b);prod = a * b;printf("PROD = %d\n", prod);return 0;}

**Beecrowd Problem 1005**

Read two floating points' values of double precisionAandB, corresponding to two student's grades. After this, calculate the student's average, considering that gradeAhas weight3.5andBhas weight7.5Each grade can be from zero to ten, always with one digit after the decimal point. Don’t forget to print the end of line after the result, otherwise you will receive“Presentation Error”. Don’t forget thespacebefore and after the equal sign.InputThe input file contains 2 floating points' values with one digit after the decimal point.OutputPrint the message "MEDIA"(average in Portuguese) and the student's average according to the following example, with 5 digits after the decimal point and with a blank space before and after the equal signal.

Input Samples |
Output Samples |

5.0 7.1 |
MEDIA = 6.43182 |

0.0 7.1 |
MEDIA = 4.84091 |

10.0 10.0 |
MEDIA = 10.00000 |

#include <stdio.h>int main() {double A, B, average;scanf("%lf %lf", &A, &B);average = ((A * 3.5) + (B * 7.5)) / (3.5 + 7.5);printf("MEDIA = %.5lf\n", average);return 0;}

**Beecrowd Problem 1006**

Read three values (variablesA,BandC), which are the three student's grades. Then, calculate the average, considering that gradeAhas weight2, gradeBhas weight3and the gradeChas weight5Consider that each grade can go from 0 to 10.0, always with one decimal place.InputThe input file contains 3 values of floating points (double) with one digit after the decimal point.OutputPrint the message "MEDIA"(average in Portuguese) and the student's average according to the following example, with a blank space before and after the equal signal.

Input Samples |
Output Samples |

5.0 , 6.0 and 7.0 | MEDIA = 6.3 |

5.0 , 10.0 and 10.0 | MEDIA = 9.0 |

10.0 , 10.0 and 5.0 | MEDIA = 7.5 |

#include <stdio.h>int main() {double A, B, C;double average;scanf("%lf %lf %lf", &A, &B, &C);average = (A * 2 + B * 3 + C * 5) / (2 + 3 + 5);printf("MEDIA = %.1lf\n", average);return 0; }

**Beecrowd Problem 1007**

Read four integer values namedA,B,CandD. Calculate and print the difference of product A and B by the product of C andD (A * B - C * D).InputThe input file contains 4 integer values.OutputPrintDIFERENCA(DIFFERENCE in Portuguese) with all the capital letters, according to the following example, with a blank space before and after the equal signal.

Input Samples |
Output Samples |

5 , 6 . 7 and 8 | DIFERENCA = -26 |

0 , 0, 7 and 8 | DIFERENCA = -56 |

5 , 6 , -7 , 8 | DIFERENCA = 86 |

#include <stdio.h>int main() {int A, B, C, D;int difference;scanf("%d %d %d %d", &A, &B, &C, &D);difference = (A * B) - (C * D);printf("DIFERENCA = %d\n", difference);return 0; }

**Beecrowd Problem 1008**

Write a program that reads an employee's number, his/her worked hours number in a month and the amount he received per hour. Print the employee's number and salary that he/she will receive at end of the month, with two decimal places. @. Don’t forget to print the line's end after the result, otherwise you will receive “Presentation Error”. @. Don’t forget the space before and after the equal signal and after the U$.InputThe input file contains 2 integer numbers and 1 value of floating point, representing the number, worked hours amount and the amount the employee receives per worked hour.OutputPrint the number and the employee's salary, according to the given example, with a blank space before and after the equal signal.

Input Samples |
Output Samples |

25 , 100 and 5.50 | NUMBER = 25 SALARY = U$ 550.00 |

1 , 200 and 20.50 | NUMBER = 1 SALARY = U$ 4100.00 |

6 , 145 and 15.55 | NUMBER = 6 SALARY = U$ 2254.75 |

#include <stdio.h>int main(){int NUMBER,hours;float amount,SALARY;scanf("%d %d %f", &NUMBER, &hours, &amount);SALARY = hours * amount;printf("NUMBER = %d\n",NUMBER);printf("SALARY = U$ %0.2f\n", SALARY);//SALARY = U$ 4100.00return 0; }

**Beecrowd Problem 1009**

Make a program that reads a seller's name, his/her fixed salary and the sale's total made by himself/herself in the month (in money). Considering that this seller receives15%over all products sold, write the final salary (total) of this seller at the end of the month , with two decimal places. @. Don’t forget to print the line's end after the result, otherwise you will receive “Presentation Error”. @. Don’t forget the blank spaces.InputThe input file contains a text (employee's first name), and two double precision values, that are the seller's salary and the total value sold by him/her.OutputPrint the seller's total salary, according to the given example.

Input Samples |
Output Samples |

JOAO – 500.00 and 1230.30 | TOTAL = R$ 684.54 |

PEDRO – 700.00 and 0.00 | TOTAL = R$ 700.00 |

MANGOJATA – 1700.00 and 1230.50 | TOTAL = R$ 1884.58 |

#include <stdio.h>int main(){double salary, value, total;char name;scarf("%s %lf %lf", &name, &salary, &value);total = salary+value*.15;printf("TOTAL = R$ %.2lf\n", total);return 0; }

**Beecrowd Problem 1010**

In this problem, the task is to read a code of a product 1, the number of units ofproduct 1, the price for one unit ofproduct 1, the code of aproduct 2, the number of units ofproduct 2and the price for one unit of product 2. After this, calculate and show the amount to be paid.InputThe input file contains two lines of data. In each line there will be 3 values: two integers and a floating value with 2 digits after the decimal point.OutputThe output file must be a message like the following example where "Valor a Pagar" meansValue to Pay. Remember the space after ":" and after "R$" symbol. The value must be presented with 2 digits after the point.

Input Samples |
Output Samples |

12 1 5.30 and 16 2 5.10 | VALOR A PAGAR: R$ 15.50 |

13 2 15.30 and 161 4 5.20 | VALOR A PAGAR: R$ 51.40 |

1 1 15.10 and 2 1 15.10 | VALOR A PAGAR: R$ 30.20 |

#include <stdio.h>int main() {int a, b;double c, res;scanf("%d %d %lf", &a, &b, &c);res = b * c;scanf("%d %d %lf", &a, &b, &c);res += b * c;printf("VALOR A PAGAR: R$ %.2lf\n", res);return 0; }

**Beecrowd Problem 1011**

Make a program that calculates and shows the volume of a sphere being provided the value of its radius (R) . The formula to calculate the volume is: (4/3) * pi * R^{3}. Consider (assign) for pi the value 3.14159. Tip: Use (4/3.0) or (4.0/3) in your formula, because some languages (including C++) assume that the division's result between two integers is another integer. :)InputThe input contains a value of floating point (double precision).OutputThe output must be a message "VOLUME" like the following example with a space before and after the equal signal. The value must be presented with 3 digits after the decimal point.

Input Samples |
Output Samples |

3 | VOLUME = 113.097 |

15 | VOLUME = 14137.155 |

1523 | VOLUME = 14797486501.627 |

#include <stdio.h> int main(){ int a; scanf("%i", &a); printf("VOLUME = %.3lf\n", (4 * 3.14159 * pow(a, 3)) / 3); return 0; }

**Beecrowd Problem 1012**

Make a program that reads three floating point values: A, B and C. Then, calculate and show: a) the area of the rectangled triangle that has base A and height C. b) the area of the radius's circle C. (pi = 3.14159) c) the area of the trapezium which has A and B by base, and C by height. d) the area of the square that has side B. e) the area of the rectangle that has sides A and B.InputThe input file contains three double values with one digit after the decimal point.OutputThe output file must contain 5 lines of data. Each line corresponds to one of the areas described above, always with a corresponding message (in Portuguese) and one space between the two points and the value. The value calculated must be presented with 3 digits after the decimal point.

Input Samples |
Output Samples |

3.0 4.0 5.2 | TRIANGULO: 7.800 CIRCULO: 84.949 TRAPEZIO: 18.200 QUADRADO: 16.000 RETANGULO: 12.000 |

12.7 10.4 15.2 | TRIANGULO: 96.520 CIRCULO: 725.833 TRAPEZIO: 175.560 QUADRADO: 108.160 RETANGULO: 132.080 |

#include <stdio.h> int main() { double a, b, c; scanf("%lf %lf %lf", &a, &b, &c); printf("TRIANGULO: %.3lf\n", (a * c) / 2); printf("CIRCULO: %.3lf\n", c * c * 3.14159); printf("TRAPEZIO: %.3lf\n", ((a + b) / 2) * c); printf("QUADRADO: %.3lf\n", b * b); printf("RETANGULO: %.3lf\n", a * b); return 0; }

**Beecrowd Problem 1013**

Make a program that reads 3 integer values and present the greatest one followed by the message "eh o maior". Use the following formula:InputThe input file contains 3 integer values.OutputPrint the greatest of these three values followed by a space and the message “eh o maior”.

Input Samples |
Output Samples |

7 14 106 | 106 eh o maior |

217 14 6 | 217 eh o maior |

#include<stdio.h> int main() { int a,b,c,major,MaiorAB; scanf("%d %d %d" ,&a ,&b ,&c); MaiorAB = (a+b+abs(a-b))/2; major = (MaiorAB+c+abs(MaiorAB-c))/2; printf("%d eh o maior",major); printf("\n"); return 0; }

**Beecrowd Problem 1014**

Calculate a car's average consumption being provided the total distance traveled (in Km) and the spent fuel total (in liters).InputThe input file contains two values: one integer valueXrepresenting the total distance (in Km) and the second one is a floating point numberYrepresenting the spent fuel total, with a digit after the decimal point.OutputPresent a value that represents the average consumption of a car with 3 digits after the decimal point, followed by the message "km/l".

Input Sample |
Output Sample |

500 35.0 |
14.286 km/l |

2254 124.4 |
18.119 km/l |

4554 464.6 |
9.802 km/l |

#include <stdio.h> int main() { double a, b; scanf("%lf %lf", &a, &b); printf("%.3lf km/l\n", a / b); return 0; }

**Beecrowd Problem 1015**

Read the four values corresponding to the x and y axes of two points in the plane, p1 (x1, y1) and p2 (x2, y2) and calculate the distance between them, showing four decimal places after the comma, according to the formula: Distance =InputThe input file contains two lines of data. The first one contains two double values:and the second one also contains two double values with one digit after the decimal point:x1 y1.x2 y2OutputCalculate and print the distance value using the provided formula, with 4 digits after the decimal point.

Input Sample |
Output Sample |

1.0 7.0 5.0 9.0 |
4.4721 |

-2.5 0.4 12.1 7.3 |
16.1484 |

2.5 -0.4 -12.2 7.0 |
16.4575 |

#include<stdio.h>#include<math.h>int main() {double x1,y1,x2,y2,d,x;scanf("%lf %lf %lf %lf",&x1,&y1,&x2,&y2);x=((pow((x2-x1),2))+(pow((y2-y1),2)));d=sqrt(x);printf("%.4lf\n",d);return 0; }

**Beecrowd Problem 1016**

Two cars (X and Y) leave in the same direction. The car X leaves with a constant speed of 60 km/h and the car Y leaves with a constant speed of 90 km / h. In one hour (60 minutes) the car Y can get a distance of 30 kilometers from the X car, in other words, it can get away one kilometer for each 2 minutes. Read the distance (in km) and calculate how long it takes (in minutes) for the car Y to take this distance in relation to the other car.InputThe input file contains 1 integer value.OutputPrint the necessary time followed by the message "minutos" that means minutes in Portuguese.

Input Sample |
Output Sample |

30 | 60 minutos |

110 | 220 minutos |

7 | 14 minutos |

#include <stdio.h>int main() {int distance;scanf("%d", &distance);int time = distance*2;printf("%d minutos\n", time);return 0; }

**Beecrowd Problem 1017**

Little John wants to calculate and show the amount of spent fuel liters on a trip, using a car that does 12 Km/L. For this, he would like you to help him through a simple program. To perform the calculation, you have to read spent time (in hours) and the same average speed (km/h). In this way, you can get distance and then, calculate how many liters would be needed. Show the value with three decimal places after the point.

**Input**

The input file contains two integers. The first one is the spent time in the trip (in hours). The second one is the average speed during the trip (in Km/h).

**Output**

Print how many liters would be needed to do this trip, with three digits after the decimal point.

Input Sample |
Output Sample |

10 85 |
70.833 |

2 92 |
15.333 |

22 67 |
122.833 |

#include <stdio.h>int main() {double a, b, r;scanf("%lf %lf", &a, &b);r = (a * b)/12;printf("%.3lf\n", r);return 0; }

**Beecrowd Problem 1018**

In this problem you have to read an integer value and calculate the smallest possible number of banknotes in which the value may be decomposed. The possible banknotes are 100, 50, 20, 10, 5, 2 and 1. Print the read value and the list of banknotes.InputThe input file contains an integer valueN(0 <N< 1000000).OutputPrint the read number and the minimum quantity of each necessary banknotes in Portuguese language, as the given example. Do not forget to print the end of line after each line, otherwise you will receive“Presentation Error”.

Input Sample |
Output Sample |

576 | 576 5 nota(s) de R$ 100,00 1 nota(s) de R$ 50,00 1 nota(s) de R$ 20,00 0 nota(s) de R$ 10,00 1 nota(s) de R$ 5,00 0 nota(s) de R$ 2,00 1 nota(s) de R$ 1,00 |

11257 | 11257 112 nota(s) de R$ 100,00 1 nota(s) de R$ 50,00 0 nota(s) de R$ 20,00 0 nota(s) de R$ 10,00 1 nota(s) de R$ 5,00 1 nota(s) de R$ 2,00 0 nota(s) de R$ 1,00 |

503 | 503 5 nota(s) de R$ 100,00 0 nota(s) de R$ 50,00 0 nota(s) de R$ 20,00 0 nota(s) de R$ 10,00 0 nota(s) de R$ 5,00 1 nota(s) de R$ 2,00 1 nota(s) de R$ 1,00 |

#include <stdio.h>int main(){int notes, aux;scanf("%d", ¬es);printf("%d\n", notes);printf("%d nota(s) de R$ 100,00\n", notes/100);aux = (notes%100);printf("%d nota(s) de R$ 50,00\n", aux/50);aux = (aux%50);printf("%d nota(s) de R$ 20,00\n", aux/20);aux = (aux%20);printf("%d nota(s) de R$ 10,00\n", aux/10);aux = (aux%10);printf("%d nota(s) de R$ 5,00\n", aux/5);aux = (aux%5);printf("%d nota(s) de R$ 2,00\n", aux/2);aux = (aux%2);printf("%d nota(s) de R$ 1,00\n", aux/1);return 0; }

**Beecrowd Problem 1019**

Read an integer value, which is the duration in seconds of a certain event in a factory, and inform it expressed in hours: minutes: seconds.InputThe input file contains an integerN.OutputPrint the read time in the input file (seconds) converted in hours: minutes: seconds like the following example.

Input Sample |
Output Sample |

556 | 0:9:16 |

1 | 0:0:1 |

140153 | 38:55:53 |

#include <stdio.h>int main() {int seconds;scanf("%d", &seconds);int hours = seconds / 3600;seconds = seconds - (hours * 3600);int minutes = seconds / 60;seconds = seconds - (minutes * 60);printf("%d:%d:%d\n", hours, minutes, seconds);return 0; }

**Beecrowd Problem 1020**

Read an integer value corresponding to a person's age (in days) and print it in years, months and days, followed by its respective message “ano(s)”, “mes(es)”, “dia(s)”.Note: only to facilitate the calculation, consider the whole year with 365 days and 30 days every month. In the cases of test there will never be a situation that allows 12 months and some days, like 360, 363 or 364. This is just an exercise for the purpose of testing simple mathematical reasoning.

Input

The input file contains 1 integer value.

Output

Print the output, like the following example.

Input Sample | Output Sample |

400 | 1 ano(s) 1 mes(es) 5 dia(s) |

800 | 2 ano(s) 2 mes(es) 10 dia(s) |

30 | 0 ano(s) 1 mes(es) 0 dia(s) |

#include <stdio.h>int main() {int total_days, years, weeks, months, days;scanf("%d", &total_days);years = total_days / 365;months = total_days % 365 / 30;days = total_days % 365 % 30;printf("%d ano(s)\n%d mes(es)\n%d dia(s)\n", years, months,days);return 0; }

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